Question

A circular coil has a 18.0 cm radius and consists of 25.0 closely wound turns of wire. An externally produced magnetic field of magnitude 3.00 mT is perpendicular to the coil. (a) If no current is in the coil, what magnetic flux links its turns?

Answer 1

The magnetic flux links to its turns =
`7.6 *10^(-3)` Wb.

Step-by-step explanation:

Given :

Radius of circular coil =
`18 * 10^(-2)` m

Number of turns = 25

Magnetic field =
`3 *10^(-3)` T

Magnetic flux (Φ) is a measure of the magnetic field lines passes through a given area. The unit of magnetic flux is weber (Wb).

We know that,

⇒ Φ =
`BA`

Where
`B =` ext. magnetic field,
`A =` area of loop or coil.

But here given in question, we have turns of wire so our above eq. modified as follows.

⇒ Φ =
`NBA`

Where
`N =` no. of turns.

∴ Φ =
`25 * 3 * 10^(-3) \pi (18 *10^(-2) )^(2)`

Φ =
`7.6 * 10^(-3) Wb`

Thus, the magnetic flux links to its turns =
`7.6 * 10^(-3) Wb`