Question

Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Complete the nuclear chemical equation below so that it describes this nuclear reaction.

____ → 30P15 + 1n0

Answer 1

Step-by-step explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.

Symbol of an alpha particle is
`^(4)_(2)\alpha`. Whereas a neutron is represented by a symbol
`^(1)_(0)n`, that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

`^(27)_(13)Al + ^(1)_(0)n \rightarrow ^(30)_(15)P + ^(1)_(0)n`