Question

An egg falls from a nest at a height of 4m. What speed will it have when it is 1m from the ground? Neglect air resistance and take g as 9.8m/s^2​

Answer 1

Answer: 7.66 m/s

Step-by-step explanation:

This situation is related to free fall (vertical motion). Hence, this can be considered a one-dimension problem and we can use the following equation:

`V^(2)=V_(o)^(2)+2gd`

Where:

`V` is the final velocity of the egg at the asked height

`V_(o)=0 m/s` is the initial velocity of the egg

`g=9.8 m/s^(2)` is the acceleration due gravity

`d=4 m- 1m= 3m` is the distance at which the egg is from the nest, when it is
`1 m` from the ground

Isolating
`V`:

`V=\sqrt{V_(o)^(2)+2gd}`

Substituting the known values:

`V=\sqrt{2(9.8 m/s^(2))(3 m)}`

`V=7.66 m/s` This is the final velocity of the egg