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Factor completely 3x^3 + 3x^2 − 18x. 3x(x + 3)(x + 2) 3x(x + 3)(x − 2) 3x(x − 3)(x + 2) 3x(x − 3)(x − 2)

Factor completely 3x^3 + 3x^2 − 18x. 3x(x + 3)(x + 2) 3x(x + 3)(x − 2) 3x(x − 3)(x + 2) 3x(x − 3)(x − 2)
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Factor completely 3x^3 + 3x^2 − 18x.

3x(x + 3)(x + 2)
3x(x + 3)(x − 2)
3x(x − 3)(x + 2)
3x(x − 3)(x − 2)

asked
User Ederag
by
8.5k points

2 Answers

6 votes

Answer:

3x(x + 3)(x − 2)

answered
User Paul Leader
by
8.6k points
4 votes

Answer:

3x(x + 3)(x − 2)

Explanation:


3x( {x}^(2) + x - 6)


3x( {x}^(2) - 2 x+ 3x - 6)


3x( \: x(x - 2) \: 3(x - 2) \: )


3x(x + 3)(x - 2)

answered
User Alexfr
by
9.0k points
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