Question

Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjacent wall. The plane of the incident and reflected beams is perpendicular to the wall. The beam from the laser strikes the mirror at a distance a = 21.7 cm a=21.7 cm from the wall. The reflected beam strikes the wall at a height b = 37.9 cm b=37.9 cm above the surface of the mirror.

Answer 1

n

Step-by-step explanation:

Answer 2

Step-by-step explanation:

According to the given situation, angle made by the reflected ray with the ground is as follows.

`\theta = tan^(-1) ((37.9)/(21.7))`

=
`60.2^(o)`

Therefore, according to the geometry of the figure.

`\theta_(r) = 90^(o) - 60.2^(o)`

=
`29.8^(o)`

Since, the angle of incidence is equal to the angle of reflection.

So,
`\theta_(i) = \theta_(r)`

=
`29.8^(o)`