Question

7. The length of a rectangle is two times its width. If the perimeter of the

rectangle can be no more than 54 units, what are the possible widths of
the rectangle?

Answer must be an inequalty, like x is less than or equal to 10 or something.​

Answer 1

The inequality should be x
`\leq` 9

Explanation:

x + 2x + x + 2x
`\leq` 54 you should change it to 6x
`\leq` 54 and divide 54 by 6 and you should get x
`\leq` 9

Answer 2

length= 2w

width=w

Explanation:

2w + w≥ 54