Question

An aqueous solution is made by dissolving 26.4 grams of copper(II) acetate in 367 grams of water. The molality of copper(II) acetate in the solution is

Answer 1

The molality of copper(II) acetate in the solution is 0.3960 mol/kg.

Step-by-step explanation:

Mass of copper(II) acetate = 26.4 g

Molar mass of copper(II) acetate = 181.63 g/mol

Moles of copper(II) acetate =-
`(26.4 g/mol)/(181.63 g/mol)=0.14535 mol`

Mass of water = 367 g = 367 × 0.001 kg ( 1 g = 0.001 kg)

`Molality(m)=\frac{\text{moles of solute}}{\text{mass of solvent (kg)}}`

`m=(0.14535 mol)/(367* 0.001 kg)=0.3960 mol/kg`

The molality of copper(II) acetate in the solution is 0.3960 mol/kg.