Question

A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.15 s.What is the average induced emf in the loop?

Answer 1

0.3405V

Step-by-step explanation:

#Given a magnetic field of
`1.9T`, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:

`\phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi* 0.0925^2 * cos 0\textdegree\\=5.107*10^-^2 \ Tm^2`

we can now calculate the induced emf,
`(\phi)/(\bigtriangleup t)`:

`(\phi)/(\bigtriangleup t)=(5.107* 10^-^2)/(0.15)\\=3.405* 10^-^1V`

Hence, the induced emf of the loop is 0.3405V