Question

Find the Sin, Cos, and Tan of the following angle:

-45 degrees

i have my teachers work here but i just don’t know the explanation of how to solve it

pleasee explain to me how to do this like my tecaher did

Answer 1

`$\sin 45^\circ=(-1)/(√(2) ), \ \cos45^\circ=(1)/(√(2) ), \ \ \tan 45^\circ=-1`

Solution:

In the given right triangle,

θ = 45°

Opposite side to θ = –1

Adjacent side to θ = 1

Hypotenuse =
`√(2)`

Using basic trigonometric ratio formulas,

`$\sin \theta=\frac{\text { Opposite }}{\text { Hypotenuse }}`

`$\sin 45^\circ=(-1)/(√(2) )`

`$\cos \theta=\frac{\text { Adjacent }}{\text { Hypotenuse }}`

`$\cos45^\circ=(1)/(√(2) )`

`$\tan \theta=\frac{\text { Opposite }}{\text { Adjacent }}`

`$\tan 45^\circ=(-1)/(1)=-1`

Therefore,

`$\sin 45^\circ=(-1)/(√(2) ), \ \cos45^\circ=(1)/(√(2) ), \ \ \tan 45^\circ=-1`