Question

Solve the system of equations.

2x+3y= 6
х+у= 4
A (6,-2)
B (-2, 6).
C (-3, 4)
D (0, 2)

Answer 1

`\text{Solve the systems of equations}\\\\2x+3y= 6\\\\x+y=4\\\\2x+3y= 6\\\\-2(x+y=4)\\\\2x+3y= 6\\\\-2x-2y=-8\\\\y=-2\\\\\text{Plug in -2 to the y value in one of the equations}\\\\x-2=4\\\\x=6\\\\\boxed{x=6\,\,y=-2}\\\\\boxed{(6,-2)}`