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For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas and in increasing order.

1 Answer

5 votes

Answer:

-10,10

Explanation:

The given quadratic equation is


k {x}^(2) + 20x + k = 0

The discriminant of this equation is given by;


D = {b}^(2) - 4ac

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.


{20}^(2) - 4 * k * k = 0

Simplify to get:


400 - 4 {k}^(2) = 0

This implies that:


400 = 4 {k}^(2)


100 = {k}^(2)

Take square root to get:


k = \pm√(100)


k = \pm10


k = - 10 \: or \: k = 10

answered
User Kelz
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