How much charge does a 9.0Vbattery transfer from the negative to the positive terminal while doing45Jof work?

Question

asked Mar 23, 2021 57.5k views

1 Answer

Merril · Answer 1 · 2021-03-29T23:54:23+0000

Answer:

q = 5 coulombs.

Step-by-step explanation:

Given :

Potential of battery , V = 9 V.

Work done in transferring charge from negative terminal to the positive terminal , W = 45 J.

We know, Work done by charge is product of its charge by its potential.

W=q* V

Therefore,
q=(W)/(V)

Putting values of W and V in above equation.

We get ,
$q=(45)/(9)=5\ coulombs.$

Hence, this is the required solution.