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Heat is transferred at a rate of 2 kW from a hot reservoir at 850 K to a cold reservoir at 300 K. Calculate the rate at which the entropy of the two reservoirs changes. (Round the final answer to six decimal places.)

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User Racoon
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1 Answer

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Answer: 3.636364 W

Explanation: entropy change S is

S = Q/T

S = 2000/(850-300)

= 3.636364W

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User Yeejuto
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