The net electric flux through an octahedron is -1850 N⋅m2/C . Part A How much charge is enclosed within the octahedron? Express your answer with the appropriate units.

Question

asked Oct 11, 2021 72.4k views

1 Answer

Soda · Answer 1 · 2021-10-18T19:31:03+0000

The electric flow is defined as the change of the charge in relation to the constant of the vacuum permittivity constant.

That is to say that mathematically this expression could be given as

$\Phi = (q)/(\epsilon_0)$

Here,

$\Phi$ = Electric Flux

q = Charge

$\epsilon_0$ = Vacuum Permittivity

Replacing with our values and solving to find q, we have,

$-1850N\cdot m^2/C = (q)/(8.854*10^(-12) C\cdot N^(-1) \cdot m^(-2))$

q = - 1.63799*10^(-8)C

Therefore the charge is enclose within the octahedron with a charge of
- 1.63799*10^(-8)C