Question

The volume of a sample of hydrogen gas was decreased from 10.54 L to 3.83 L at constant temperature. If the final pressure exerted by the hydrogen gas sample was 6.59 atm, what pressure did the hydrogen gas exert before its volume was decreased?

Answer 1

Answer: 2.39 atm

Step-by-step explanation:

To calculate the initial pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

`P_1V_1=P_2V_2`

where,

`P_1\text{ and }V_1` are initial pressure and volume.

`P_2\text{ and }V_2` are final pressure and volume.

We are given:

`P_1=?\\V_1=10.54L\\P_2=6.59atm\\V_2=3.83L`

Putting values in above equation, we get:

`P_1* 10.54=6.59* 3.83\\\\P_1=2.39atm`

Thus initial pressure hydrogen gas exerted before its volume was decreased was 2.39 atm