Question

at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were only 75 percent of its original value

Answer 1

Answer: The percent change in volume will be 25 %

Step-by-step explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` are the initial volume and temperature of the gas.

`V_2\text{ and }T_2` are the final volume and temperature of the gas.

We are given:

`V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75* T_1`

Putting values in above equation, we get:

`(2L)/(T_1)=(V_2)/(0.75* T_1)\\\\V_2=(2* 0.75* T_1)/(T_1)=1.5L`

Percent change of volume =
`\frac{\text{Change in volume}}{\text{Initial volume}}* 100`

Percent change of volume =
`((2-1.5))/(2)* 100=25\%`

Hence, the percent change in volume will be 25 %