asked 209k views
2 votes
Find the horizontal asymptote of the graph of y= -2x^6+5x+8/8x^6+6x+5

a: y= -1/4

b: y=0

c= y=1

D= no horizontal asymptote

NEED HELP ASAP!!!!

asked
User Keronda
by
7.8k points

2 Answers

3 votes

Answer:a) y = -¼

Explanation:

(-2x^6+5x+8)/(8x^6+6x+5)

Just divide the leading coefficients

answered
User Basir Alam
by
8.3k points
7 votes

Answer:

a) y = -¼

Explanation:

(-2x^6+5x+8)/(8x^6+6x+5)

Just divide the leading coefficients

-2/8 = -¼

Horizontal asymptote:

y = -¼

answered
User Compositr
by
8.6k points

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