Question

Find the area of the isosceles triangle with legs 12 and base 17. Simplify all radicals

a2+b2=c2

Answer 1

`Area= (17 √(865) )/(4) \: {units}^(2)`

Explanation:

From Pythagoras theorem,

`{h}^(2) = {12}^(2) + { ((17)/(2) )}^(2)`

`{h}^(2) = (865)/(4)`

`h = ( √(865) )/(2)`

The area of the isosceles triangle is

`Area= (1)/(2) bh`

`Area= (1)/(2) * 17 * ( √(865) )/(2) = (17 √(865) )/(4)`