Question

A person applies a 13.5 N force to a hammer while it moves a distance of .12 m. The hammer completes 1.56 J of work on the nail. What is the efficiency of the hammer? Must show all work, correct sig figs, and include correct units.

Answer 1

=96.29%

Step-by-step explanation:

Work efficiency is the ratio of output to input expressed as a percentage

Work is the product of fore and distance.

Work input =13.5*0.12=1.62 J

Work output= 1.56 J

Efficiency= 1.56/1.62 *100

=96.29%