What volume will 1.27 moles of helium gas occupy at stp

Question

asked Jul 21, 2021 210k views

2 Answers

AlienDeg · Answer 1 · 2021-07-25T19:50:44+0000

Answer:

28.45L

Step-by-step explanation:

1mole of a gas occupy 22.4L at stp. This implies that 1mole of He also occupy 22.4L at stp.

Now if 1mole of He occupied 22.4L at stp, then, 1.27mol will occupy = 1.27x22.4 = 28.45L