Question

In a poll, respondents were asked if they have traveled to Europe. 68 respondents indicated that they have traveled to Europe and 124 respondents said that they have not traveled to Europe. If one of these respondents is randomly selected, what is the probability of getting someone who has traveled to Europe?

Answer 1

T= A person selected in the poll travel to Europe

NT= A person selected in the poll NOT travel to Europe

For this case we have the following respondents for each event

n(T)= 68

n(NT) = 124

So then the total of people for the poll are:

`n = n(T) + n(NT)= 68 +124= 192`

And we are interested on the probability of getting someone who has traveled to Europe, and we can use the empirical definition of probability given by:

`p =(Possible)/(Total)`

And if we replace we got:

`p = (n(T))/(n)= (68)/(192)= 0.354`

So then the probability of getting someone who has traveled to Europe is 0.354

Explanation:

For this case we define the following events:

T= A person selected in the poll travel to Europe

NT= A person selected in the poll NOT travel to Europe

For this case we have the following respondents for each event

n(T)= 68

n(NT) = 124

So then the total of people for the poll are:

`n = n(T) + n(NT)= 68 +124= 192`

And we are interested on the probability of getting someone who has traveled to Europe, and we can use the empirical definition of probability given by:

`p =(Possible)/(Total)`

And if we replace we got:

`p = (n(T))/(n)= (68)/(192)= 0.354`

So then the probability of getting someone who has traveled to Europe is 0.354