Question

the student determines the molar mass of the gas to be 64 g mol-1. write the expression (set-up) for calculating the percent error in the experimental value, assuming that the unknown gas is butane (molar mass 58 g mol-1). calculations are not required

Answer 1

Percentage error =
`((64 - 58))/(58)` x 100%

Step-by-step explanation:

In order to calculate the percentage error in the student's calculation, the following formula will be used:

Percentage error =
`((experimental molar mass - theoretical molar mass))/(theoretical molar mass)` x 100%

experimental molar mass = 64 g/mol

theoretical molar mass = 58 g/mol

Hence, the expression becomes:

Percentage error =
`((64 - 58))/(58)` x 100%