Question

Question 7 (7 points)

Jackson is building a small rectangular basketball section in his backyard. The
length of the section will be 1.25 times the width of the section.
Part A (2 POINTS)
Create an equation to represent the area of the basketball section, A, in terms of
the width, w.
Part B (5 POINTS)
Jackson decides to make the area of the basketball section 245 square feet. What
are the dimensions, in feet, of the basketball section?
SHOW ALL WORK TO RECEIVE FULL CREDIT!!!

Answer 1

• A = 1.25w²
• width: 14 ft; length 17.5 ft

Explanation:

A) The length is 1.25 times the width. The width is represented by w, so the length (L) is ...

L = 1.25w

The area (A) is the product of length and width, so is ...

A = Lw = (1.25w)(w)

A = 1.25w²

__

B) The width of the section can be found by using the given area and solving for w:

245 = 1.25w²

196 = w² . . . . . . . . divide by 1.25

14 = w . . . . . . . . . . take the square root

L = 1.25·14 = 17.5 . . . . find the length

The dimensions of the section are 14 feet wide by 17.5 feet long.