If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI 10.4 moles NaCI 2.6 moles NaCI 5.2 moles NaCI 2 moles NaCI

Question

asked Apr 19, 2021 201k views

1 Answer

Troy Sabin · Answer 1 · 2021-04-26T06:05:31+0000

Answer:

5.2moles of NaCl

Step-by-step explanation:

The equation for the reaction is:

2Na + Cl2 —> 2NaCl

From the equation,

2moles of Na produced 2moles of NaCl.

Therefore, 5.2moles of Na will also produce 5.2moles of NaCl