Question

A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N , against a friction force of 210 N . What is the acceleration of the box?

Answer 1

Therefore the acceleration of the box is
`(2)/(3)` m/s²

Step-by-step explanation:

Force: Force is defined as the product of mass the object and acceleration of the object.

F= m×a

F= force

m= mass

a = acceleration

Friction: Friction is one kind of force , against the moment of an object.

Here, two types of force are applied on the object.

Horizontally force which is along the displacement.

and the friction force is opposite direction of the displacement.

Total force
`F= F_h-F_f`

`F_h= 230 N` and
`F_f= 210N` mass (m)= 30 kg

We know that

F= m×a

`\Rightarrow a=(F)/(m)`

`\Rightarrow a=(F_h-F_f)/(m)`

`\Rightarrow a=(230-210)/(30)`

`\Rightarrow a=(2)/(3)` m/s²

Therefore the acceleration of the box is
`(2)/(3)` m/s²