Answer:
The answer is 71.61%.
 
Explanation:
Households discarding paper week is given to be normally distributed with a mean, 
 = 9.4 lb.
 = 9.4 lb.
The normally distributed distribution has a standard deviation given as 
 = 4.2 lb.
 = 4.2 lb.
The proportion of households that throw out at least 7 lb of paper a week is to be found.
Therefore we have to find p(X ≥ 7) which can be written as
 p(X ≥ 7) = 1 - p(X < 7)
 = 1 - p( Z < 
 )
 ) 
 = 1 - p( Z < 
 )
 )
 = 1 - p( Z < -0.571 ) 
 = 1 - 0.2839
 = 0.7161
Therefore the percentage of households that throw out at least 7 lb paper a week is 71.61%