Find θ, 0° ≤ θ < 360°, given the following information. cos θ = -(√(3) )/(2) and θ in QII θ = ________°

Question

Find θ, 0° ≤ θ < 360°, given the following information.

cos θ =
`-(√(3) )/(2)` and θ in QII
θ = ________°

Answer 1

Θ = 150°

Explanation:

Given

cosΘ = -
`(√(3) )/(2)`, then

Θ =
`cos^(-1)` ( -
`(√(3) )/(2)` ) = 150° ← angle in second quadrant