Answer:
99.4 g of O are formed in 6.21 moles of KOH
Step-by-step explanation:
KOH → Potassium hydroxide
1 mol of KOH has 1 mol of K, 1 mol of O and 1 mol of H
Therefore, 6.21 moles of KOH have 6.21 moles of O
Let's convert the moles to mass: 6.21 mol . 16 g/1 mol = 99.4 g