Question

What are the zeros of f(x) = x2 - 8x + 16?

O
A. x = -4 and x = 4
O B. x = -4 only
O c. x= 4 only
O
D. x = -2 and x = 8

Answer 1

Explanation:

`f(x) = {x }^(2) - 8x + 16 \\ \therefore \: f(x) = (x - 4)^(2) \\ when \: f(x) = 0 \\\implies (x - 4)^(2) = 0 \\ \therefore \: x - 4 = 0 \\ \therefore \: x= 4 \: only`