Question

A bat is flitting about in a cave, navigating via ultrasonic bleeps. Assume that the sound emission frequency of the bat is 37.5 kHz. During one fast swoop directly toward a flat wall surface, the bat is moving at 0.021 times the speed of sound in air. What frequency does the bat hear reflected off the wall?

Answer 1

39.11 Hz

Step-by-step explanation:

Data provided in the question:

Frequency of sound emission,
`f_0` = 37.5 kHz = 37500 Hz

Speed of bat,
`v_(bat)` = 0.021 times the speed of sound

Now,

Frequency heard by bat =
`f_0*((v+v_(bat))/(v-v_(bat)))`

Therefore,

The Frequency heard by bat will be =
`37500*((343+0.021*343)/(343-0.021*343))`

or

Frequency heard by bat will be=
`37500*(350.203)/(335.797)`

or

Frequency heard by bat will be = 39108.78 Hz = 39.11 Hz