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Two parallel surfaces move relative to each other are separated by a gap of 0.375 in. The gap is filled by a fluid of with .00431 lb-sec/in2 viscosity. The relative motion is re…
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Two parallel surfaces move relative to each other are separated by a gap of 0.375 in. The gap is filled by a fluid of with .00431 lb-sec/in2 viscosity. The relative motion is re…
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Sep 10, 2021
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Two parallel surfaces move relative to each other are separated by a gap of 0.375 in. The gap is filled by a fluid of with .00431 lb-sec/in2 viscosity. The relative motion is resisted by a shear stress of 0.25 lb/in2 due to the viscosity of the fluid. What is the velocity of the parallel surfaces above assuming the velocity gradient in the space between the surfaces is constant?
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Answer:
Velocity will be 21.75in/sec
Diagram well explains the calculation.
Nllsdfx
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