Question

If Vm were clamped at -40 mV, what would the driving force be for Na+ to cross the cell membrane? What would be the driving force for K+? g

Answer 1

-35 mV and +56 mV

Step-by-step explanation:

The membrane potential is the energy that is needed to drive membrane changes across the phospholipid bi-layer membrane.

Ions can move in and out of the cell through protein channels. The movement of the ions is as a result of concentration that affect the operation of ion gates.

The reverse potential is given by the Nernst equation:

`E_(ion) = (RT)/(zF) ln(ion_(outside) )/(ion_(inside) )`

where, R = gas constant

T = temperature (Kelvin)

z = ion charge

F = Faraday's charge

The potential is calculated and the result is -35 mV and +56 mV respectively.