asked 142k views
5 votes
What is the center and radius of the circle?
(x-3)2 + y² = 4

asked
User WoelliJ
by
7.8k points

1 Answer

6 votes

Answer:

center = (3, 0)

radius = 2

Explanation:

Standard equation of a circle:
\sf (x-h)^2+(y-k)^2=r^2

(where (h, k) is the center of the circle and r is the radius)

Given equation:


\sf (x-3)^2+y^2=4

Rewrite in standard form:


\sf \implies (x-3)^2+(y-0)^2=2^2

Therefore

  • center = (3, 0)
  • radius = 2
answered
User Pani
by
7.4k points

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