asked 232k views
2 votes
Sally has a polygon that is proportional to Jack's polygon, but hers has nine times as much area as his. How much larger are the sides of sally's polygon?

asked
User Marnina
by
7.3k points

1 Answer

7 votes

Answer:


ls=3l_(J)

Explanation:

Let Sally's polygon be for example a square (As) where the area is equal to the square side and Jack (Aj) has a proportional one but Sally's is nine times larger than the Jack, then:


As=9A_(J)\\A_(J)=l^(2)_(J)\\As=9A_(J)\\As=l^(2)s\\replacing\\l^(2)s=9A_(J)\\l^(2)s=9l^(2)_(J)\\\sqrt{l^(2)s}=\sqrt{9l^(2)_(J)}\\ls=3l_(J)

Sally has a polygon that is proportional to Jack's polygon, but hers has nine times-example-1
answered
User Zhar
by
8.2k points
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