Question

A 1.08 x 103 kg car uniformly accelerates for 12.0 s from rest. During this time the car

travels 132 m north. Find the net force acting on the car during this acceleration.​

Answer 1

5940N

Step-by-step explanation:

Given parameters:

Mass of car = 1.08 x 10³kg = 1080kg

Time for acceleration = 12s

Displacement = 132m

Unknown:

Net force = ?

Solution

According to newton's second law of motion; "the acceleration of a body is directly proportional to its force and inversely proportional to mass".

F = m x a

F is the net force

m is the mass

a is the acceleration

Acceleration =
`(V - U)/(t)`

V is the final velocity

U is the initial velocity

t is the time taken

To find the final velocity here which is V;

V =
`(displacement)/(time)` =
`(132)/(12)` = 11m/s

since the body accelerates uniformly from rest, U = 0

Now, solve for acceleration;

A =
`(11 - 0)/(12)` = 5.5m/s²

So;

F = ma

F = 1080 x 5.5 = 5940N