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5 votes
What are the solution(s) for the quadratic equation?

f(x)=x^2+12x+36

Please show work!

asked
User Teppic
by
7.9k points

1 Answer

7 votes

Let's see


\\ \rm\rightarrowtail x^2+12x+36=0


\\ \rm\rightarrowtail x^2+6x+6x+36=0


\\ \rm\rightarrowtail x(x+6)+6(x+6)=0


\\ \rm\rightarrowtail (x+6)(x+6)=0


\\ \rm\rightarrowtail x=-6

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