Christopher is packing his bags for his vacation. He has 8 unique shirts, but only 5 fit in his bag. How many different groups of 5 shirts can he take?

Question

asked Jan 28, 2021 32.3k views

1 Answer

Surfasb · Answer 1 · 2021-02-01T17:56:21+0000

Answer:

He can take 5 shirt of 56 different group.

Explanation:

Given, Christopher is packing his bags for his vacation. He has 8 unique shirts , but only 5 fit in his bag.

$^8C_5=\frac{ {8!}}{5!(8-5)!} =(8!)/(5!3!) =56$

He can take 5 shirt of 56 different group.