How many moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess?

Question

asked Aug 12, 2021 175k views

2 Answers

Kumar Anand · Answer 1 · 2021-08-19T13:23:45+0000

Answer: The number of moles of
NaCl produced will be, 3.61 moles.

Explanation : Given,

Mass of
= 83.0 g

Molar mass of
= 23 g/mol

First we have to calculate the moles of

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=(83.0g)/(23g/mol)=3.61mol$

Now we have to calculate the moles of
NaCl

The balanced chemical equation is:

$2Na+Cl_2\rightarrow 2NaCl$

From the reaction, we conclude that

As, 2 mole of
react to give 2 mole of
NaCl

So, 3.61 mole of
react to give 3.61 mole of
NaCl

Therefore, the number of moles of
NaCl produced will be, 3.61 moles.