Question

3x^3 - 2y^-6x^2y^2+xy for x=2/3 and y=1/2

Answer 1

-13

Explanation:

3x^3 - 2y^-6x^2y^2+xy

x=2/3 and y=1/2

Solve :

3x^3 - 2y^-6x^2y^2+xy

Put value of x and y in this equation

= 3(2/3)^3 - 2(1/2)^-6(2/3)^2(1/2)^2+(2/3)(1/2)

= -13