Question

Identify the logarithmic form of 4^−2 = 0.0625.

Answer 1

`\log_4{(0.0625)}=-2`

Explanation:

The logarithmic form of ...

`\displaystyle b^e=v`

is ...

`\log_b{(v)}=e`

The exponent is the logarithm of the value. The base of the logarithm is the base of the exponential term.

Filling in your numbers, b=4, e=-2, v=0.0625, you have ...

`\log_4{(0.0625)}=-2`