Question

Consider this mating between genotypes AaBBccDd and AabbCCDd, where A, B, C and D are loci that assort independently and the uppercase and lower case letter indicate the dominant allele and recessive allele respectively. a. What is the probability that any given offspring of this pair will be heterozygous at all loci?b. What is the probability that an offspring will be homozygous at all four loci?c. What is the probability that an offspring will be phenotypically dominant?

Answer 1

Step-by-step explanation:

AaBBccDd x AabbCCDDd ---Parents

Aa x Aa = AA (1/4), Aa (1/2) & aa (1/4)

BB x bb = Bb (1)

cc x CC = Cc (1)

Dd x Dd = DD (1/4), Dd (1/2), dd (1/4)

a). The probability that any given offspring of this pair will be heterozygous at all loci = AaBbCcDd = ½ * 1*1*1/2 = ¼

b). The probability that an offspring will be homozygous at all four loci =AABBCCDD = ¼*0*0*1/4 = 0

c). The probability that an offspring will be phenotypically dominant = A_B_C_D_ = ¾ * 1 * 1* ¾ = 9/16