asked 218k views
23 votes
How many solutions are there?

How many solutions are there?-example-1
asked
User Fleur
by
8.1k points

2 Answers

3 votes

Answer:

No solution

Explanation:

Simplify the L.H.S and the R.H.S


6(2k + 1) = 12k + 1


12k + 6 = 12k + 1

Cancel out the "12k"


12k + 6 = 12k + 1


6 = 1 (\text{False})

Henceforth, this equation has no solution.

answered
User Werner Henze
by
7.4k points
6 votes

Answer:

no solution

Explanation:

Solve:

6(2k + 1) = 12k + 1

Expand brackets:

⇒ 12k + 6 = 12k + 1

Subtract 12k from both sides:

⇒ 6 = 1

As 6 ≠ 1 there is no solution

answered
User Andyhasit
by
8.4k points

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