When A and B are mutually exclusive, P(A or B) can be found by adding P(A) and P(B). A. True B. False

Question

asked Oct 3, 2021 62.8k views

1 Answer

Jooyong · Answer 1 · 2021-10-07T03:33:38+0000

Answer:

True

Step-by-step explanation:

We have given that P(A) and P(B) are mutually exclusive

Mutually exclusive means there is no common element in A and B

So
$P(A\cap B)=0$

We know that
$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

As A and B are mutually exclusive and so
$P(A\cap B)=0$

Putting this value in
$P(A\cup B)$

$P(A\cup B)=P(A)+P(B)-0=P(A)+P(B)$

From the above equation we can see that
$P(A\cup B)$ is the sum of
and
P(B)

So the given statement is true statement