Question

You drive a car 1600 ft to the east, then 2500 ft to the north. The trip took 2.5 minutes. What was the magnitude of your average velocity?

Answer 1

`Velocity=6.03m/s`

Step-by-step explanation:

Given data

Time t=2.5 minutes=150 seconds

Distance A=1600 ft=487.68 m........east

Distance B=2500 ft=762m ........north

To find

Average velocity

Solution

First we need to find the resultant distance magnitude.To find that we apply Pythagorean theorem to find hypotenuse

So

`A^(2)+B^(2)=C^(2)\\ C=\sqrt{A^(2)+B^(2)}\\ C=\sqrt{(487.68m)^(2)+(762m)^(2)}\\ C=904.7m`

`Velocity=(Distance)/(Time)\\Velocity=(904.7m)/(150s)\\Velocity=6.03m/s`