Question

Find rhe area of a cjircle of radius 35 cm if a sector of angle80 is removed from the circle what area is left

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Answer 1

Removed area

`\\ \sf\longmapsto A=(\theta)/(360)\pi r^2`

`\\ \sf\longmapsto A=(80)/(360)\pi r^2`

`\\ \sf\longmapsto A=(2)/(9)\pi r^2`

Left area.

`\\ \sf\longmapsto \pi r^2-(2)/(9)\pi r^2`

`\\ \sf\longmapsto \pi r^2(1-2/9)`

`\\ \sf\longmapsto \pi r^2(7/9)`

`\\ \sf\longmapsto 7/9(35)^2\pi`

`\\ \sf\longmapsto 952.7\pi cm^2`

Answer 2

• 2991.72 cm²

Explanation:

Find the area left:

• A =
• πr² - 80/360*πr² =
• πr²(1 - 2/9) =
• 7/9πr² =
• 7/9*3.14*35² =
• 2991.72 cm²