Question

Find the area of triangle ABC to the nearest tenth. In , a = 11, c = 11, and B = 100°.

Answer 1

area ≈ 59.6 units²

Explanation:

Calculate the area (A) of the triangle using

A =
`(1)/(2)` ac sinB

That is one half the product of the 2 sides and the sine of the included angle, thus

A =
`(1)/(2)` × 11 × 11 × sin100° ≈ 59.6 units² ( to the nearest tenth )