Question

Dave has several golf balls in his golf bag. Seven of them are brand A, 9 are brand B, and 2 are brand C. He reaches into the bag and randomly selects one golf ball, then he selects a second one without replacing the first one. What is the probability that the first one is a brand A golf ball and the second one is a brand C golf ball?

Answer 1

Step-by-step explanation:

Given

bag contain

7 balls of brand A

9 balls of brand B

2 balls of brand C

Dave randomly select the a ball and then a second ball without replacement of first ball

Probability that first ball is A golf ball
`P(A)=(7)/(18)`

Probability that second ball is of brand C
`P(C)=(2)/(17)`

Probability that the first one is a brand A golf ball and the second one is a brand C golf ball
`=P(A)* P(B)`

`=(7)/(18)* (2)/(17)=(7* 2)/(18* 17)=(14)/(306)=0.045`