Question

If both zeroes of quadratic polynomial (k+2)x^2-(k-2)x-5 are equal in magnitude but opposite in sign find k

Answer 1

k=2

Explanation:

`(k + 2) {}^(2) - (k - 2)x - 5 = 0`

If we have two zeroes that are equal in size, but different signs then we have a different of squares,

`(a + b)(a - b) = {a}^(2) - b {}^(2)`

So in order to do this we must make the middle term, x 0 so

`k - 2 = 0`

`k = 2`