Question

If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.100 mm length of the axon?

Answer 1

Charge enter a 0.100 mm length of the axon is
`8.98* 10^(-12) C`

Step-by-step explanation:

Electric field E at a point due to a point charge is given by

`E=k (q)/(r^2)`

where
`k` is the constant =
`9.0 * 10^9 Nm^2 / C^2`

`q` is the magnitude of point charge and
`r` is the distance from the point charge

Charges entering one meter of axon is
`5.* 10^(11) * (+e)`

Charges entering 0.100 mm of axon is
`5.* 10^(11) * (+e) * (0.1 * 10^(-3)`

substituting the value of
`+e=1.6* 10^(-19) C` in above equation, we get charge enter a 0.100 mm length of the axon is

`q=5.* 10^(11) *1.6* 10^(-19) * (0.1 * 10^(-3)\\q=8.98* 10^(-12) C`