Question

A hat contains four red marbles, two blue marbles, seven green marbles, and one orange marble. If two marbles are picked out of the hat randomly, what is the probability that one will be orange and one will be blue?

A. 98 percent
B. 1/98
C. 3/14
D. 1/7
E. 3 percent

Answer 1

Answer: B.
`(1)/(98)`.

Explanation:

Given : A hat contains four red marbles, two blue marbles, seven green marbles, and one orange marble.

Total marbles = 4+2+7+1 = 14

P(Blue)=
`(2)/(14)=(1)/(7)`

P(Orange) =
`(1)/(14)`

if we randomly select two marbles , then the probability of selecting one will be orange and one will be blue marble = P(Blue) x P(Orange) [both events are independent]

`=(1)/(7)*(1)/(14)=(1)/(98)`

Hence, the probability that one will be orange and one will be blue is
`(1)/(98)`.

Therefore , the correct answer is B.
`(1)/(98)`.